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Getan expert solution to n = 3, l = 2, m =0, m s = -1/2 For an electron having quantum numbers given above, calculate the orbital angular momentum:
In co m e b e f o r e p r o v i s i o n f o r l o a n l o s s e s $ 1 4 7 , 3 8 5 $ 1 2 0 , 5 7 1 $ 1 3 6 , 5 4 4 $ 3 9 3 , 4 3 1 $ 4 0 4 , 6 9 5 F in a n c ia l p o s it io n ( $ i n t h o u s a n d s )
Ar e a l t o r 's e - ma i l a d d r e s s i s u s e d t o c o n t a c t a n e s c r o w c o m p a ny t o
Subject Chemistry, asked on 8/3/11 i) n=3 , l = 1 , m=1 , s= +1/2 ii) n = 4 l = 1 m = 1 s = +1/2 iii) n =1 l=0 m=o s=+1/2 iv) n=2 l=2 m=1 s=+1/2 which are the possible set of quantum no.s? why? pls explain it clearly. Share with your friends 1 Follow 0 Shveta Dua, Meritnation Expert added an answer, on 9/3/11 Dear Student,
. No two electrons in an atom can have the same set of quantum numbers. The first quantum number is the principle quantum number , which is n=3. This means the electron is in the third energy level shell. The second quantum number, the angular momentum , is l=2, and means the electron is in the "d" sublevel subshell. The third quantum number, the magnetic quantum number , m_l=2, represents one of the five "3d" orbitals. Lastly, we have the spin quantum number , m_s=-1/2. It indicates the direction of the spin of the electron. Each electron in an atom has a unique set of quantum numbers. The given quantum numbers for the electron in the question tell us that there is a high probability that the electron is in one of the "3d" orbitals of the atom. Resources
De acordo com o modelo atômico atual, a disposição dos elétrons em torno do núcleo ocorre em diferentes estados energéticos. Para o elétron mais energético do átomo de ferro no estado fundamental, os números quânticos principal e secundário são, concomitantemente Z = 26 a 3 e 0 b 3 e 2 c 4 e 0
n 3 l 2 m 1 s 1 2